Thanks for help the other day with my previous questions regarding EC experiments!
I got the data and I have also got an idea for another experiment where I would like to present pictures in various combinations.
(Brace yourself because that’s a bit of reading below…but I would totally appreciate your time here)
Main idea: there will be 12 photos of neutral valence (let’s call them CSs) which will be paired with photos of either positive or negative valence (let’s call them USs) and I would like to show them in a way that one CS will be always paired with only one US at once, but within a block of trials the same CS will in some trials be presented with a positive US and in other ones with a negative US (e.g. 1 trial CS1 presented with US positive 1; 2 trial CS1 presented with US negative 1, etc.).
Then, after the ‘learning phase’ is finished I would like to present all the 12 CSs presented before (neutral photos) to the participants when they are always accompanied by two USs at the same time, but in two different conditions:
Condition 1 (positive condition)
Presenting CSs always with the actual positive USs and always wrong negative USs at once
e.g., CS1 presented with the positive US1 (that it was really paired with before) and one of the US of negative valence (e.g. US negative 4 instead of US negative 1), but not the real negative US1 that it was in fact paired with
Condition 2 (negative condition)
Presenting CSs always with wrong positive USs and always the actual negative USs at once
e.g., CS1 presented with the negative US1 (that it was really paired with before) and one of the US of positive valence (e.g. US positive 4 instead of US positive 1), but not the real positive US1 that it was in fact paired with
Well, that would be pretty much so far…and I wonder whether this is possible to do in OS and whether you might have some ideas of how to do that?
Is there a way to zip CSs and USs somehow, so that I am sure what was paired with what?
I know it’s probably messy and confusing to read, but I would be super grateful for your feedback on that.