Set an incompressible duration of sketchpad while recording response time

Comments

• eduard

  March 2017

  Hi,

  How about some python scripting? Set the duration of the sketchpad to 0 and replace the keyboard with an inline_script in which you will collect the response:

  
  kb = keyboard(timeout = 0)
  blank = canvas()
  start_time = clock.time()
   var.correct = NA
  var.resp_time = NA
  while True:
      k,t = kb.get_key()
      if k != None:
           var.resp_time = t-start_time
           var.correct = k==var.correct_response
           break
      if clock.time()-start_time > 3000:
          blank.show()
      elif clock.time() - start_time > timeout:
           break
  

  Edaurd

  
• Neuro_student

  March 2017

  Thanks Eduard, the thing is that I don't know anything about Python...
  I did a copy/paste and it didn't work (It tells me variable "correct" doesn't exist). I guess that I should add some informations in this code but I really don't know what and how...
• eduard

  March 2017

  I see.

  
  kb = keyboard(timeout = 0) # initializes a keyboard response item with a timeout of 0 
  blank = canvas() # makes an empty canvas
  var.correct_response = 'd' # define what you consider a correct response.
  start_time = clock.time() # start time of reaction time measure
  var.correct = NA # initialize correct response variable
  var.resp_time = NA # initialize response time variable
  # loop for as long as you want, e.g. 10 seconds
  timeout = 10000
  while True:
      k,t = kb.get_key() # sample key response
      if k != None: # if a key was pressed ...
           var.resp_time = t-start_time  # ... measure response time
           var.correct = k==var.correct_response # and define whether response was correct
           if clock.time()-start_time > 3000: # if response was given after 3 seconds, ....
                 break # break the loop
      if clock.time()-start_time > 3000: # after 3000 seconds
          blank.show() # show an empty canvas
      elif clock.time() - start_time > timeout: # after a certain time (defined earlier) ...
           break # break the loop
  

  YOu can also check out the documentation. It's not all that difficult:

  http://osdoc.cogsci.nl/3.1/manual/python/about/
  http://osdoc.cogsci.nl/3.1/manual/python/keyboard/

  Eduard

  
• Neuro_student

  March 2017

  Hi Eduard,

  So I did the necessary to understand a bit python code but I still don't succeed.

  What I would like to have is :
  If a key is pressed but the response time is inferior at 3000ms : collect response time and correct response + my picture stays on the screen until it reaches this 3000ms of presentation (and unfortunately this until function doesn't exist...) and then move on to the next picture.
  If this is not the case : wait with my picture on the screen until the participant answers and then collect all informations and continue on next picture.

  Do you have any idea of what I should do ?
• Neuro_student

  March 2017

  
• eduard

  March 2017

  Did you try my code? It should work I think...

  kb = keyboard(timeout = 0) # initializes a keyboard response item with a timeout of 0 
  my_canvas = copy_sketchpad('my_sketchpad') # makes an empty canvas
  var.correct_response = ['q','m'] # define what you consider a correct response.
  start_time = clock.time() # start time of reaction time measure
  var.correct = NA # initialize correct response variable
  var.resp_time = NA # initialize response time variable
  # loop for as long as you want, e.g. 10 seconds
  timeout = 10000
  while True:
      k,t = kb.get_key() # sample key response
      if k != None: # if a key was pressed ...
           var.resp_time = t-start_time  # ... measure response time
           var.correct = k==var.correct_response # and define whether response was correct
           if clock.time()-start_time > 3000: # if response was given after 3 seconds, ....
                 break # break the loop
           else:
                 clock.sleep(timeout-(clock.time()-start_time) )
      if clock.time()-start_time > 3000: # after 3000 seconds
          blank.show() # show an empty canvas
      elif clock.time() - start_time > timeout: # after a certain time (defined earlier) ...
           break # break the loop
  

  Btw. Please post code as text, not as image, this makes working with it a lot easier.

  Eduard

  
• Neuro_student

  March 2017

  I found something much easier which works as I want.

  self.sleep(3000-self.get('response_time'))

  Thank you a lot for your help !

  Ysia