[solved] get path of the experiment file
Hi. I'm wondering if it is possible to automatically obtain the path of the current opensesame file. The reason is that I want opensesame to search for the stimuli inside a folder placed in the same path of the experiment file. I don't want to use the file pool because I have about 2000 images, so opensesame is slow in loading and saving the experiment. On the other hand, of course I can provide the absolute paths to the sketchpad, but then I will have to modify them when I move the experiment on the laboratory PC.
Thanks.

Comments
Hi,
The
get_file()function first looks in the file pool and then looks in the folder of the current experiment. Sopath = exp.get_file("my_image.png")will return the full path of the image, even if it's not stored in the file pool but merely in the same folder as your experiment. And you're right, storing your stimuli this way will make loading and saving much faster!Fore more info, see:
Does this help?
Best,
Lotje
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Yes, but in my case the stimuli are in a subfolder of the folder of the current experiment. Have I necessarily to move the opensesame file inside the stimuli folder? I would prefer to leave a folder with only the pictures because in this way everything looks neater.
Hi,
Imagine that your image are in the "images" folder of the current experiment.
Then I guess that
path = exp.get_file("\\images\\my_image.png")should work...Hi boris. Unfortunately it does not work.
Hi Andrea,
You could determine the experiment folder by using the built-in Python module
os:Alternatively, you could use exp.get_file() like so:
path = exp.get_file('subfolder/image.png')Best wishes,
Lotje
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Ok, solved! I was doing and incorrect use of the exp.get_file() function.
Many many thanks.
Great to hear!
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