SART loop and lists

Comments

• eduard

  November 2019

  Hi,

  My problem is that I can't figure out how to present sequentially each number from the built list in a trial sequence.

  If you have a trial sequence (Opensesames loop/sequence structure), you need a variable that counts iterations, e.g. trial number. This variable you can then use to index the number list you generated.

  Does that help? If not, could you provide more details on the thing you want, and the things that doesnt work?

  Thanks,

  Eduard

  
• zyko

  November 2019

  Hi eduard,

  If you have a trial sequence (Opensesames loop/sequence structure), you need a variable that counts iterations, e.g. trial number. This variable you can then use to index the number list you generated.

  You're totally right! I previously used a counter variable in a previous opensesame experiment. However, I can't manage to set a counter variable for the stimuli from the list.

  
  

  My experiment is as follow:

  

  experimental_loop should set the number of numbers to display (5 blocks that should be randomly used 2 times).

  I set a script that built a stimulus list in the prepare section of the create_stimulus_list script (it seems to work well outside opensesame).

  import random
  NumberOfTrials = var.number_of_stimuli #5 blocks, see experimental_loop, get the number of stimuli to display for the selected block
  NumberOfTarget = int(0.11*NumberOfTrials) #no more than 11% of Target in the total trials per block
  NonTargetList = [1,2,4,5,6,7,8,9]
  Target = 3
  var.NumberList = []
  prev1 = 10 #Will be used to avoid repetition of the same stimulus in consecutive positions
  prev2 = 10
  ##var.number_dur = 500
  ##var.isi = 2000
  var.Number = []
  
  
  while len(var.NumberList) < NumberOfTrials-NumberOfTarget:#Prepare a list of n NonTarget stimuli minus n Target stimuli for a total number equal to the number_of_stimuli variable
  	NonTarget = random.choice(NonTargetList) #Pick up a random NonTarget stimulus
  	if NonTarget not in [prev1,prev2]: #if loop in order to avoid same consecutive number
  		Target = 3
  		var.NumberList.append(NonTarget)
  		prev2 = prev1
  		prev1 = NonTarget
  if NumberOfTarget == 1: #if there is only 1 Target stimulus, put it in a random position except the first one
  	var.NumberList.insert(random.randint(1,len(var.NumberList)),Target)
  else: #if there are more than 1 Target stimulus, generate n random non successive index and no more than requested number of Target that will be used to insert Target stimuli into the list of stimuli
  	indxList = random.sample(range(1,NumberOfTrials-NumberOfTarget+2),NumberOfTarget)
  	##print(indxList)
  	i=0
  	while i < NumberOfTarget:
  		idx=indxList[i]
  		var.NumberList.insert(idx,Target)
  		i=i+1
  

  There is a trial sequence (trial_coroutines) that should display sequentially the numbers from the list of stimuli.

  Now, I'm stuck in the way to pick up the numbers and display them one after another. I tried to set a variable stocking the numbers in an iterative way but I lamentably failed :/

  Thanks,

  Alex
• eduard

  November 2019

  Hi Alex,

  Could you try to use "count_stimulus_presentation" as counter variable? Alternatively, you can also add a variable to your block loop table.

  Eduard

  
• zyko

  November 2019

  Hi eduard,

  I think I found the tip.

  I set a counter_trial variable before the block_loop and update it in the trial_coroutines.

  I also set a number_to_display variable in the trial_coroutines sequence that get the number in the number_list variable following the counter_trial that serves as the index for the number_list.

  Finally, I set the block_loop repeat to the number_of_stimuli value from the experimental_loop.

  I must beta-test it but all numbers of the created number_list are now displayed sequentially for each block.
• zyko

  November 2019

  Could you try to use "count_stimulus_presentation" as counter variable?

  I tried something like this by using count_trial_coroutines. However, I could not reset the variable.

  Actually, it counts the trial_coroutines through all block. Thus, in the second block, the first number displayed was the index_in_the_stimulus_list_of_the_second_block = number_of_stimuli_from_the_first_block
• eduard

  November 2019

  Makes sense. Good to hear!