[solved] Displaying an inline-generated variable in the sketchpad.
Hi.
I'm having a very hard time doing what I thought would be a rather simple task using OpenSesame.
I'm trying to generate a random number (using the inline script) and display it on the screen using the sketchpad.
my humble script:
import random
beg = 10
end = 19
leftnum = random.randint(beg,end)
r = range(beg,leftnum) + range(leftnum+1, end)
rightnum = random.choice(r)
This actually generates two numbers (rightnum and leftnum), and now I want to display these two variables/numbers using the sketchpad.
Simply creating a text object and filling it with [leftnum] or [rightnum] doesn't work.
calling them var.leftnum and var.rightnum inside the script also fails.
Is there any simple way to do this?
Thanks for the help.
Comments
Hi Zennie,
You're almost there! In order to use a variable outside of the inline_script, you have to make it 'available' elsewhere in your experiment, by means of
exp.variable = 'your_number', orexp.set('number', str(leftnum)+str(rightnum)). In your sketchpad you should then be able to use [number].Cheers,
Josh
Thanks for the help, but It's still not working.
Just to make sure I follow you:
I have added
to the end of my inline script.
Now in the sketchpad I use a textline element where I insert [leftnum] as the text.
Running the experiment, I get the error: "The variable 'leftnum' does not exist. Tip: Use the variable inspector (Ctrl+I) to see all variables."
Am I doing something wrong?
BTW, the sketchpad is located just after the inline script, under the same sequence.
Solved it.
Thanks to Josh who helped.
All I needed to do after setting the variable was to move the entire code to the prepare tab (and not the run tab) in the inline script.
Apparently, the sketchpad is getting ready before the inline code is running, so it does not get the new variable I defined.
Hi Zennie,
Great that you've solved it. Just to avoid problems in the future: if you create a variable like this
exp.variable = 'leftnum', you'll end up with a variable that literally contains a string 'leftnum'. I gave the exampleexp.variable = 'your_number', but that is assuming you already have a concrete number like '56'. You created a variableleftnumthat contains the number, hence, you want to useexp.variable = leftnum, so that your new variable uses the value that leftnum refers to, rather than the string 'leftnum'.Cheers
Josh