Next Button doesn't work and using Input for Feedback

Ad300

Hey there!!
1) My Next Button doesn't work. It only works if I don't answer the question which is on the same form.- Counterproductive :

2) I want to use my answer collected by the form to give feedback and use it all troughout the experiment. I put the variable name of the textinput [text_input] in a feedback Item after my form but it doesnt show anything.

I used 2 Inlinescripts and one feedback_item where I wrote [text_input], in that order.

First Inlinescript:

    import random
    import numpy as np
    from numpy import random as nprand

    def create_matrix():
      # determine the random number of ones and zeros to be put into the lists
      c0_min = 20 # minimal number of zeros
      c0_var = 5 # range of possible additional zeros
      c0 = int(nprand.rand()*c0_var + c0_min) # count of zeros

      c1_min = 20 # ones
      c1_var = 20 
      c1 = int(nprand.rand()*c1_var + c1_min) # count of zeros

      # construct a long list with ones and zeros of random order
      # items
      items = [0,]*c0 + [1,]*c1
      random.shuffle(items)

      # determine the length of the rows 1-4
      # there is a minimal length + a variable length
      # len of rows
      lmin = 10
      rowcount = 4
      spacemax = 5

      # determine the number of characters that are freely assignable (total number minus minimal length)
      l_temp = c0+c1-lmin*rowcount # variable assignable characters

      # divide residual characters with respect to random weights among the rows
      l_weights = nprand.rand(4)
      l_weights = l_temp*l_weights/sum(l_weights)
      s_count = nprand.randint(0,spacemax,4)

      # calculate the final lengths of the rows
      r1 = lmin + int(l_weights[0])
      r2 = lmin + int(l_weights[1])
      r3 = lmin + int(l_weights[2])
      r4 = lmin + int(l_weights[3])

      # construct the strings by iterating the previously shuffled character list
      s1 = ''.join([str(i) for i in [' ', ]*s_count[0] + items[:r1]]) + "\n"
      s2 = ''.join([str(i) for i in [' ', ]*s_count[1] +  items[r1:(r1+r2)]]) + "\n"
      s3 = ''.join([str(i) for i in [' ', ]*s_count[2] +  items[(r1+r2):(r1+r2+r3)]]) + "\n"
      s4 = ''.join([str(i) for i in [' ', ]*s_count[3] +  items[(r1+r2+r3):]])

      # return row 1-4, number of zeros, number of ones.
      return {"rows": s1+s2+s3+s4, "c0":c0, "c1":c1}

    m = create_matrix()
    print m["rows"]
    var.grid = m["rows"]
    # this is mockup code
    tmarker = 10
    timer = 5
    print m['c0']

    var.kbresponse = int()
    # end of mockup code
    var.h = str(m["c0"])
    #m["c0"] = count zero,..

** Second Inlinescript:**

    from libopensesame import widgets
    form = widgets.form(exp, cols=[1,1], rows=[1,1,1,1,1])
    title = widgets.label(form,
        text='Indicate how much you agree with the following statement')
    question1 = widgets.label(form, text=var.grid, center=False)

    nextButton = widgets.button(form, text='Next')
    form.set_widget(title, (0,0), colspan=2)
    form.set_widget(question1, (0,0))

    form.set_widget(nextButton, (0,4), colspan=2)
    form._exec


    var.text_input = widgets.text_input(form, text="Wieviele Nullen befinden sich in dem Zahlenblock:", var='response',
            return_accepts=True)
    form.set_widget(var.text_input, (0,3))
    form._exec()

Any pointers would be great!!!

eduard

Hi,

Attached the modified experiment that should work.

1) My Next Button doesn't work. It only works if I don't answer the question which is on the same form.- Counterproductive

This is because you have activated the option return_accept = True. In order to proceed, you have to hit return. If you set return_accept to False, then you have to press the next button in order to proceed.

2) I want to use my answer collected by the form to give feedback and use it all troughout the experiment. I put the variable name of the textinput [text_input] in a feedback Item after my form but it doesnt show anything.

Not sure what went wrong in your case, but in the attached example, it does work. So if you set var = 'Response', then you can call the the variable with var.Response, or [Response] henceforth.

Hope this helps.

Eduard