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Comments
Hi Mollie,
I think I roughly understand what you're trying to do, but the devil is in the details.
Could you first explain exactly how you select the stimuli at the moment? What are the constraints? In what sense are you counterbalancing things (as the name of the
counterbalancing_1
item suggests)? And how exactly does the script (which is pretty dense) accomplish this?Next, could you explain exactly what the constraints are for these repeated trials? E.g. are they sampled from the same set as the other stimuli? How often should they occur? Can they occur twice in a row, etc.?
Cheers!
Sebastiaan
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Hey Sebastiaan!
Thank you so much. At the moment the stimuli are paired such that object_5 and object_6 are always together. I have objects named object_5 through object_21.
That is why I have the stim_match_1 and stim_match_2 part of the script so that those pairs always show up together.
As of now, there are no repeated objects, which is how I want it.
Basically, if it randomly selects object_6 that means it must also randomly select object_5 and that if object_5 shows up on the left then object_6 must show up on the right. Then, either object_5 or object_6 will be the top card(target). If the target is 6 then the subject must press the square on the right where object 6 was. (because they are a match).
Additionally, I do not want the answer to be on the same side more than three times in a row which is the bottom part of the counterbalance_1.
This is all exactly how I wanted it for the first design.
Now, I want everything to remain the same, that is the same object pairs should stay together and be randomly assigned left or right and target, the correct answer should not be on the same side more than three times in a row, and the object pairs should not repeat. BUT, I now want one object pair to repeat over and over again and be 'sandwiched' between the non-repeated randomly selected pairs of objects.
My current design is like so
object_5 and object_6
object 19_ and object_20
object_9 and object_10
Until 8 trials have happened and all pairs have been shown one time.
What I would like to happen is:
object_8 and object_7
object_1 and object_2
object_9 and object_10
object_1 and object_2
object_14 object_13
object_1 and object_2
etc. until all 8 pairs have been shown, none of them repeated, with the same answer not on the same side more than three times in a row.
So same exact paradigm, just with a repeated pair every other. importantly, this repeated pair should follow the same randomization rules such that sometimes object_1 is on the right and object_2 is on the left and the target(top card) is the match for object_1. Sometimes, object_1 is on the right and object_2 is on the left and the target(top card) is the match for object_2. Sometimes, object_2 is on the right and object_1 is on the left and the target(top card) is the match for object_1. Sometimes, object_2 is on the right and object_1 is on the left and the target(top card) is the match for object_2.
Sorry I know this is rather involved. I hope I did an ok job explaining it. I appreciate any help you are able to offer. Thank you so much again.
Best,
Mollie
Hi Mollie,
I think I understand now. The main trick would be to add a repetition target (
target_1
in my example) after every regular target. This is done in the 'randomise variables' part of the script. Then, you need to also add a matching stimulus forobject_1
, i.e.object_2
. And finally thetarge_side
list should be twice as long as before, because we now have twice as many trials, i.e. 16 instead of 8.Does that get you started?
Sebastiaan
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Perfect!! Thank you so so much
Hey Sebastian!
The only thing is that I don't want the target to always be the same in the repetition trials. Sometimes I want it to be object 1 and sometimes I want it to be object 2. I'm having trouble with the randomization of this here. Any help would be greatly appreciated!
Thank you so much,
Mollie
Hi Mollie,
If I understand the logic correctly, then would simply change this line:
To this:
Cheers!
Sebastiaan
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Hi Sebastian,
Thank you so so much again. I'm getting an error. I notice there is a missing parenthesis but when I add another it still gives me an error. Any advice?
Thanks,
Mollie
Any advice?
Yes, to post the actual error message ?
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Hi Sebastian,
It gives me a weird error as I haven't changed anything with var.targets.
If I change the parenthesis to
targets_with_repetitions.append(choice(['object_1', 'object_2']))
I get:
Thank you so much again!
Mollie
Hi Mollie,
The problem is that 'object_2' is a key in the
stim_match_1
dict. I updated the code above to show how you can add it (marked 'update').Cheers!
Sebastiaan
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thank you!!!