Variable Timeout

Comments

• eduard

  November 2019

  Hi Tobi,

  in an inline_script, you can compute the new timeout.

  It is important to put the code in the run phase, because otherwise no response will be defined.

  jitter = 2000 # or whatever you want
  var.star_dur = 2500 - var.resp_time + jitter
  

  Importantly, the star then needs to be shown in the feedback item, not a sketchpad. See here why:

  https://osdoc.cogsci.nl/3.2/manual/prepare-run/

  Good luck,

  Eduard

  
• Mkengine

  December 2019 edited December 2019

  Thank you, that solved my problem. Though I have another little thing: I want to show the text "Wrong!" when the wrong key was pressed and "Too slow!" when nothing was pressed, but if I use [correct] as variable for "Wrong" it is shown when nothing was pressed as well, so what variable do I have to use?

  Additionally, I want to use a custom keyboard, is there an easy way to implement this?
• eduard

  January 2020

  Hi,

  What do you mean with custom keyboard?

  Splitting the feedback into wrong and too late is possible, for that you need to use an additional variable though. For example, you can use var.response which indicates whether a response was given, so if [response] = 'None' and [correct]=0, then you would want to show too late, otherwise wrong.

  Good luck,

  Eduard

  
• Mkengine

  January 2020

  Hi, thanks for the help.

  With 'custom keyboard' I mean a response pad with 4 buttons, which can be accessed via ports, so I can't just use the normal keyboard response, but had to write an inline script where I access the port. I tried the following code, but I get an 'invalid syntax' (I think for the if condition), do you know why, and if the code would be working as intended?

  
  

  timeout_start = clock.time()

  timeout = 2000

  while clock.time() < timeout_start + timeout:

  var.response = io.DlPortReadPortUchar(port+1)

  if var.response == (4 or 5 or 6 or 7)

  var.response_time = clock.time() - timeout_start

  break
• sebastiaan

  January 2020

  @Mkengine You have asked the exact same question in this post. Please don't do that in the future, and help us keep the forum clean!

  
  
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• Mkengine

  January 2020

  Sorry, I won't do that again. After some time I just thought this thread was buried and it's faster to open a new one.