Inline code keyboard response code automatically sets the end of the trial

Comments

• eduard

  December 2023

  HI Patxi,

  Your code doesn't include how you compute the variable jittered_time Can you add that info?

  by the way, your trial_rt variable is computed the wrong way (not related to your question.

  Eduard

  
• patxelos

  December 2023

  Hi Eduard,

  Thanks for your quick reply! I believe I've resolved the issue by subtracting the response time from the jitter duration, ensuring the ITI remains unaltered by the response. It's currently working well, and the timing appears accurate, but I'm curious if there might be a more efficient or safer approach to achieve this. Your insights would be greatly appreciated.

  

  Best,

  Patxi

  p.d.: jittered time is just a float
• eduard

  December 2023

  Hi Patxi,

  A slightly more efficient approach would be this:

  kb.flush()
  start_time = ITI_fix.show() 
  k, t = kb.get_key()
  if k is not None: 
      trial_rt = t - start_time
  clock.sleep(jittered_time - trial_rt)
  

  With kb = Keyboard(keylist=['1'], timeout=3500) being put before the loop (you only need to initialize it once, not on every trial). However, in practice the two versions would be almost identical.

  Eduard

  
• patxelos

  December 2023

  Thank you so much Eduard! This code snippet works perfectly fine and it is definitely more elegant than my solution. In terms of timing there isn't any substantial difference.

  Best,

  Patxi