[solved] using feedback variable like 'acc' in an inline script
Hi all
In my experiment, I want to stop and inform the experimenter by a beep whenever a participant's accuracy drops beneath 50% in the practice block.
To achieve this, I used the following inline script code immediately after the practice loop:
if self.get('acc') < 50:
from openexp.synth import synth
my_synth = synth(exp, freq='A1', length=500)
my_synth.play()
but, it is not working.
when i typed:
print self.get('acc')
nothing is printed
but when using [acc] in a feedback item I get the correct accuracy
any idea how can I achieve my goal?
Nir
Comments
i would insert a synth object from the GUI into your sequence and do run if [acc]<50. Also you said you inserted the script immediately after the practice loop. This means it will not beep during the practice loop, only after the participant has completed the practice loop
Hi Joshua.
Thanx for the reply.
Your suggestion for binding the sound and accuracy graphically is good and I will probably use it for this specific task.
But, I am more interested in a python solution. both because I like to code better than to use graphical builders and because I want to use more sophisticated condition than the one I listed above.
Not getting a value for 'acc' when using it in a code is my main issue here.
Nir
Hi Nir,
Although I agree with @JoshuaBaker that a run-if statement in a
sequencewould be the easiest solution, your script should work as well.You mention that you see nothing in the debug window when you run ...
... but do see the correct accuracy when using
[acc]in afeedbackitem. Since[acc]andself.get('acc')refer to the same thing, this suggests that you have put your code in the prepare phase of yourinline_script, whereas it should be in the run phase. For an explanation, see also:Does that clear things up?
Cheers,
Sebastiaan
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thanx sebastiaan
My code was written in the "run" phase but it was written
print ( self.get('acc') )instead ofprint self.get('acc')Normally in python it's dose not matter matter
Glad to hear you resolved things. Both the
printstatement andprint()function work though (as they do in general in Python 2), so the problem was likely somewhere else. Please let me know if you can reproduce a difference in behavior between the two, because they should be interchangeable.Check out SigmundAI.eu for our OpenSesame AI assistant!