Multiple blocks

Comments

• fladd

  December 2016 edited December 2016

  Hi rrr,

  maybe like this?

  import expyriment as xpy
  
  exp = xpy.design.Experiment()
  
  # Let's assume there is a variable 'stimuli' that is a list of 200 trials
  
  xpy.design.randomize.shuffle_list(stimuli)
  
  for counter, stim in enumerate(stimuli):
      if counter % 20 == 0:
          b = xpy.design.Block()
      t = xpy.design.Trial()
      t.add_stimulus(stim)
      b.add_trial(t)
      if counter % 20 == 19:
          exp.add_block(b)
  
  # 'exp.blocks' should now contain 10 blocks with 20 trials, each holding a single stimulus.
  

  Warning There was an error rendering this rich post.
• rrr

  December 2016

  Hello,

  It goes well, but how can I randomize completely all of trials throughout an experiment in the case of multiple factorial designs?
  When we want to have a two-way factorial design, the program as below runs without any errors but the order of trial is completely separated into two. The first half of trial results in factor 1, and the latter half does in factor 2.

  import expyriment
  
  exp = design.Experiment()
  
  # importing a list of 200 trials
  Factor1 = [s_list]
  design.randomize.shuffle_list(stimuli)
  
  Factor2 = [100, 200]
  
  for duration in Factor2:
      for counter, stim in enumerate(stimuli):
          if counter % 20 == 0:
              b = design.Block()
          t = design.Trial()
          t.set_factor("Factor1", stim)
          t.set_factor("Factor2", duration)
          t.add_stimulus(stim)
          b.add_trial(t)
          if counter % 20 == 19:
              block.shuffle_trials()
              exp.add_block(b)
  
• rrr

  December 2016

  I was able to divide an experiment into the multiple blocks with all shuffled trials as below, referring to your suggestion and the number classification task example of Expyriment.

  def run_trial(cnt, trial):
     #define a trial
  
  control.start(exp)
  
  for block in exp.blocks:
      for cnt, trial in enumerate(block.trials):
          if cnt % 20 == 0:
              instruction.present()
              exp.keyboard.wait()
          run_trial(cnt, trial)
  

  In this case, the blocks are divided just by inserting an instruction every 20 trial, so the data of block id are not saved in the file.

  Is there any way to save the block id?